Question

Please help! simplify. x^2+4x-21 over x+7 times x-3 over x^2-5x+6

Answer 1

=(x^2+(7x-3x)-21)/(x+7)
=(x^2+7x)-(3x+21)/(x+7)
=x(x+7)-3(x+7)/(x+7)
=(x-3)(x+7)/(x+7)
=(x-3) (1)
now we do the 2nd part
(x-3)/(x^2-5x+6)
=(x-3)/(x^2-3x-2x+6)
=(x-3)/(x(x-3)-2(x-3))
=(x-3)/((x-3)(x-2)
=1/(x-2) (2)
now multiplying 1 nd 2
(x-3) /(x-2)...... ans

Answer 2

is it helped

Answer 3

thank you!

Answer 4

u welkum
:P