Question

factoring polynomials 7a^2x-6a^2-7x+6

Answer 1

7a^2x-6a^2-7x+6


(7a^2x-6a^2)+(-7x+6)


a^2(7x-6)+(-7x+6)


a^2(7x-6)-1(7x-6)


(a^2-1)(7x-6)


(a-1)(a+1)(7x-6)


So 7a^2x-6a^2-7x+6 factors to (a-1)(a+1)(7x-6)


In other words 7a^2x-6a^2-7x+6=(a-1)(a+1)(7x-6)