Question

2x^2+xy-3y^2

Answer 1

2x^2+xy-3y^2


2x^2+3xy-2xy-3y^2


(2x^2+3xy)+(-2xy-3y^2)


x(2x+3y)+(-2xy-3y^2)


x(2x+3y)-y(2x+3y)


(x-y)(2x+3y)


So 2x^2+xy-3y^2 factors to (x-y)(2x+3y)


In other words, 2x^2+xy-3y^2=(x-y)(2x+3y)