Question

WRITE AN EQUATION OF A LINE IN STANDARD FORM WITH THE GIVEN SLOPE THROUGH THE GIVEN POINT -2/3(6,9)

Answer 1

the standard form of a straight line is
y= mx+b
where m is the gradient, and b the y intercept (ie when x=0, y=b)
m = -2/3,
every point on the line satisfies this formula, so we can use a known point to solve for b
the point (x,y) = (6,9) in this case so we can write
x = 6, y=9

substituting the gradient and the point into the formula give us..
9=(-2/3)6+b solving for b
9=-4+b
b=13

With the gradient and the intercept
y=(-2/3)x+13