Question

WRITE AN EQUATION OF A LINE IN STANDARD FORM WITH THE GIVEN SLOPE THROUGH THE GIVEN POINT -2/3(6,9)

Answer 1

The slope is the change in y over the change in x.
\[(y _{1}-y _{2})/(x _{1}-x_{2})\]
you know two of the x and y values already.
\[(9-y _{2})/(6-x_{2})\]
You also know the slope; -2/3
So you know
\[(9-y )/(6-x)=-2/3\]

Then rewrite as an equation. You can do it.

Answer 2

use general form
y-y1 = m(x-x1)

y-9 = -2/3 (x - 6)
y-9 = -2/3x + 4
y + 2/3x = 13
3y + 2x = 39