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factorize: b^4-ab^3+b^2c
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\[b ^{4}-ab ^{3}+b ^{2}c\]
b^2(b^2-ab+c)
b^2(b^2-ab+c)
\[b^2(b^2-ab+bc)\]
bc? kira
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no...kira's wrong...b^2 (bc) woulbe be b^3c
Sorry my error... \[b^2 (b^2 - ab +c)\] What's happening to me today? Not in the best condition...
b\[b ^{2}(b ^{2}-a+c)\]
kpo you forgot the ab
u put ab in u get \[ab ^{3}\]
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oh ..its cube.sry
i thought it was a square.
close though
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