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what is the eccentricity of the ellipse (x+7)^2/16+(y-3)^2/4=1
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type in into your calculator joonam
the e value i believe is c/a
a^2 is the bigger of the 2 denoms; and b^2 the smaller; then to find c we utilize the pythag thrm b^2 + c^2 = a^2
c^2 = 16 - 4 c^2 = 12 c = 2sqrt(3) e value = 2sqrt(3)/4 = sqrt(3)/2 if i recall it correctly
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