Question

If R(x)=50x- x^2/50 and dx/dt=10, then what is dR/dt at x=375?

Answer 1

Do you know if the right answer is -100?

Answer 2

nope

Answer 3

Well, I'll tell you what I did.
Using the chain rule:
\[dR/dt = d(5x)/dx * dx/dt - d(x ^{2}/50)/dx * dx/dt\]

Answer 4

\[dR/dt = 5*dx/dt - (2x/50) * dx/dt\]
From there you should be able to get it.

Answer 5

ok thanks!