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Sqrt(x+2)+4= x
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\[\sqrt{(x+2)=x-4}\] now squaring both sides (taking attention that x has to be bigger or equal than -2) \[x+2=x^2-8x+16\] \[x^2-9x+14=0\] \[(x-2)(x-7)=0\] so x=2 or x=7
careful here. 7 works and 2 does not
when you square you have to check your answer
true, thanks
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