Question

I need help with : Express the domain of the given function using interval notation

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Answer 1

\[f(x)\sqrt{2x ^{2}-8}\]

Answer 2

f(x)=*

Answer 3

2x^2 - 8 > 0
2x^2 = 8
x^2 = 4
x =2 , -2

take values : smaller than -2 - > -3
between -2 and 2 -> 0
larger than 2 3

2(-3)^2 - 8 = 2 * 9 - 8 = 10 positive
2*(0)^2 - 8 = -8 negative
2*(3)^2 - 8 = 2*9-8 =10 positive

so x<-2 or x>2

interval notation

(-infinity,-2) or (2,infinity)

Answer 4

thanks so much!