Question

Find the polar arc length of r=1/θ (π≤θ≤2π)
I need some help for the integration part.

Answer 1

did you calculate ds? the sqrt of r^2 + dr/dtheta squared

Answer 2

I got \[s=\int\limits_{\pi}^{2\pi} \sqrt{(1/\theta)^2+(-1/\theta^2)^2}d \theta\]
then I don't know how to integrate it.