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Mathematics 13 Online
OpenStudy (anonymous):

4+x^-1/3+x^-1

OpenStudy (nubeer):

hmm u need to put brackets in here too. hard to understand the exact question

OpenStudy (anonymous):

[4+(x^-1)]/[3+(x^-1)]

OpenStudy (nubeer):

taking l.c.m which makes [4(x) +1/x]/[3(x) +1/x] cancel out x [4x+1] /[3x+1]

jhonyy9 (jhonyy9):

4 +1/x ------- = (4+1/x)*(1/(3+1/x)) 3+1/x

jhonyy9 (jhonyy9):

4x+1 x 4x+1 ----- * ------ = ------- x 3x+1 3x+1

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