Question

How to find the x-intercept of f(x)=3x^2+6x+2

Answer 1

0 = 3x^2 + 6x + 2
quadratic formula :

(-6 +/- ((36-24)^0.5) / 6
-1 +/- (8^0.5)/6

x1,2 = -1 +/- (2^0.5)/3

so x1 = -1 + (2^0.5)/3
x2 = -1 - (2^0.5)/3