Question

solve for all values of x
\[1/4^{1-2x} =32\]

Answer 1

\[\frac{1}{4^{1-2x}} =32\]

\[\frac{1}{2^{2(1-2x)}} =2^5\]

\[2^{-2(1-2x)} =2^5\]

\[-2(1-2x) =5\]
\[1-2x =-\frac{5}{2}\]
\[-2x =-\frac{5}{2}-1=-\frac{7}{2}\]
\[x=\frac{7}{4}\]

Answer 2

thank you very much :)