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solve for all values of x (9/25)^x =5/3
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\[9/25^{x}=5/3\]
sigh :(. this is very simply \[\log_{9/25} (5/3)\] which using the base change formula is: log (5/3) / log (9/25)
If you sqaure the RHS and then flip it you get the LHS
x=(-1/2)
thankyou very much :)
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