Question

Use the sum or different to find he exact value of each trigonometric function
a) tan(π)/(12)

Answer 1

Do you know what the period of the sin function is?

Answer 2

note that
\[\frac{\pi}{12}=\frac{\pi}{3}-\frac{\pi}{4}\] and use the subtraction angle formula for tangent

Answer 3

Remember,\[\tan(x)=\frac{\sin(x)}{\cos(x)}.\]

Answer 4

Oh, the asker meant\[\tan(\frac{\pi}{12}).\]

Answer 5

http://openstudy.com/users/mandolino#/users/mandolino/updates/4e86d5720b8b7ce881cf43a3

Answer 6

\[\tan(\alpha - \beta)=\frac{\tan(\alpha)-\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}\]

Answer 7

so you get
\[\tan(\frac{\pi}{3}- \frac{\pi}{4})=\frac{\tan(\frac{\pi}{3})-\tan(\frac{\pi}{4})}{1-\tan(\frac{\pi}{3})\tan(\frac{\pi}{4})}\]