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solve. x=log[5](1/25) a. 2 b. 1/5 c. -2 d. 5square root of 0.04 e. none
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\[5^{-2}=\frac{1}{25}\]
Ok. What is log[5] 5 ?
The relationship between an exponential and a log is the following\[y=\log_{b}x \iff b^y=x\]in english that mean when you are trying to evaluate a log, you ask yourself the question: to what power do I have to raise the base b to get the argument of the log, x
btw, your NEXT post is the opposite question to the first one I answered a few minutes ago
answer to this one is C
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by opposite you mean log6 216=3??
yes since 6^3=216
well played, yardbird
thank you
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