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OpenStudy (anonymous):
Solve for x: 81^x = 27^-x
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jimthompson5910 (jim_thompson5910):
81^x = 27^(-x) (3^4)^x = (3^3)^(-x) 3^(4x) = 3^(-3x) since the bases are equal, the exponents are equal, so 4x = -3x 4x+3x = 0 7x = 0 x = 0/7 x = 0
OpenStudy (anonymous):
OMG Ty !
jimthompson5910 (jim_thompson5910):
yw
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