Question

integral 1/2 to sqrt 3/2 6/sqrt of 1-t^2

Answer 1

is this
\[6\int_{\frac{1}{2}}^{\frac{\sqrt{3}}{2}}\frac{1}{\sqrt{1-t^2}}dt\]?

Answer 2

anti derivative of
\[\frac{1}{\sqrt{1-t^2}}\] is
\[\sin^{-1}(x)\] so you can evaluate at upper limit, lower limit, subtract, and then multiply the result by 6