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4 times the lesser of the two consecutive even intergers is 12 less than twice the greater #'s . what are the intergers, and how did you get them?
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4[x+(x+2)] = 2[(x+4)+(x+6)] - 12
4(2x+2) = 2(2x+10) - 12 8x + 8 = 4x + 20 - 12 8x + 8 = 4x + 8 4x + 8 = 8 4x = 0 x = 0 I'm not sure if I'm right because I'm half sleep.. I don't think so xD.. Anyone care to assist me?
i know that the answer is -4,-2 but im not quite sure how.
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