Question

Find the exact zeros.
F(x)=x^3-7x^2+13x-3

Answer 1

the rational zeros are factors of -3/ factors of 1
they can be 1,-1,3,-3
testing gives 3 as a zero. divide the polynomial by x-3 in order to get a quadratic equation. Now find the zeros of that equation. And you get it. :)

Answer 2

Ok I was right! Thank you so much! my exact zeros turn out to be \[3, 2+ \sqrt{3}, 2-\sqrt{3}\]