write an equation in slope intercept form the y axis and explain
? rephrase or complete the problem
numbers 21 and 23
hello
y axis has no slope.
its vertical. the slope would be divide by 0....
y=mx+b 23) -2, -4 slope of - 1/2 -4=(-1/2)(-2)+b
im confused can u show the work
for 21 and 23
for 21) y = -infinity to infinity x=0 =no slope y=8, x=0 8=m0+b the whole line is the intercept
23) y=mx+b y=-4 x=-2 m=-1/2 find b -4=(-2)(-1/2)+b -4=1+b
b=-5 y=-1/2 x-5
for 23 thats in standard form
can u upload the work step by step for 23
please
its right there copy and paste. its in slope intercept form
dont be a lazy douche
no i think 23 is in standard form
i upload the problem
hello are u there
hello
The equation for the y-axis is x=0. For the other problem they tell you y, m, and x at a point. You need the slope-intercept form of the line which is y=mx+b. For their given point you know all of those values except b, which you can solve for easily. Then just directly write down the equation using the value they gave you for m and the value you found for b. And tutordiffeq already did all the work.
somebody please help me with numbers 15 17 19 21 23
With all of those?
I only see 26 - 32. I think you posted the wrong page
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