Question

if a rectangle has on side as 12 and another as x. and a different rectangle has 2-x as one side and 16 as another, find the value of x so that the rectangles have the same area.

Answer 1

12x = 16(2-x)
12x = 32 - 16x
28x = 32
x = 32/28

Answer 2

\[\Delta _{1}=12(x)\]
\[\Delta _{2}=16(2-x)\]
If\[\Delta _{1}= \Delta _{2}\]
12(x)=16(2-x)
12x=32-16x
28x=32
x=32/28
=8/7