Question

The sum of three mixed numbers is 20 4/15
Two of the numbers are 5 1/3 and 5 5/6
What is the third number?

- Please teach me how to work this out! ><

Answer 1

subtract the 2 given numbers from the total to find whats left over

Answer 2

or we could simply set it up as such:

\[5\frac{1}{3}+5\frac{5}{6}+N=20\frac{4}{15}\]
and solve for N

Answer 3

thank you :)!

Answer 4

a mixed numeral is simply addition; if you have 5 and you add 1/3 of another to it; you get: 5 + 1/3 = 5' 1/3

Answer 5

I would try it out like this:
\[5\frac{1}{3}+5\frac{5}{6}+N=20\frac{4}{15}\]
\[5+\frac{1}{3}+5+\frac{5}{6}+N=20+\frac{4}{15}\]
\[5(3)+\frac{1(3)}{3}+5(3)+\frac{5(3)}{6}+(3)N=20(3)+\frac{4(3)}{15}\]
\[15+1+15+\frac{5}{2}+3N=60+\frac{4}{5}\]
\[31+\frac{5}{2}+3N=60+\frac{4}{5}\]
\[31(2)+\frac{5(2)}{2}+3(2)N=60(2)+\frac{4(2)}{5}\]
\[62+5+6N=120+\frac{8}{5}\]
\[67+6N=120+\frac{8}{5}\]
\[67+(-67)+6N=120+(-67)+\frac{8}{5}\]
\[6N=53+\frac{8}{5}\]
\[6(5)N=53(5)+\frac{8(5)}{5}\]
\[30N=265+8\]
\[30N=273\]
\[\frac{30N}{30}=\frac{273}{30}\]
\[N=\frac{273}{30}\]
im sure there are steps you could do in your head, but it pretty much comes to this

Answer 6

i got 9 3/30 but i don't think it's right.

Answer 7

oh! i got it right when i put 9 1/10. THANKY YOU!

Answer 8

youre welcome