two planes are 7700 miles apart, and their speeds differ by 300 mph. They travel toward each other and meet in 7 hours. Find the speed of the slower plane.

Question

amistre64 · Answer

hmm .....

7700 - t -(t+300) = 0, perhaps?  its worth a shot

amistre64 · Answer

7700 - t -t -300 = 0

7400 - 2t  = 0

7400 = 2t

7400/2 = t = 3700 miles .... but thats prolly a side effect of what I was thinking to begin with since i measured distance instead of time

anonymous · Answer

Which one should I do then? :)

amistre64 · Answer

|dw:1317583291446:dw|

anonymous · Answer

Okay hold on.. I'm going to try it out.

amistre64 · Answer

we equate the speeds and cover the distance

7700 = 7s + 7(s+300)

7700 = 7s + 7s+2100

  7700 = 14s +2100
-2100            -2100
-------------------
 5600 = 14s


s = 5600/14, but id dbl chk it forst

amistre64 · Answer

if thats done right; the one plane is going 400mph while the other is going 700mph

the distance covered when added should be 7700 miles

anonymous · Answer

I got 400?

amistre64 · Answer

7700 = 7(400) + 7(700)

7700 = 2800 + 4900

7700 = 7700

so yes, the slower is going 400

anonymous · Answer

Yes! I got it! Your the best :)) Thankyou!

amistre64 · Answer

yep, youre welcome; and i tend to think of myself as the penultimate mathmatiker lol

anonymous · Answer

I believe it! I would have never gotten that without you. Whats your name?

amistre64 · Answer

.... amistre64

anonymous · Answer

No like you REAL name. Like mine is Joyce :) lol