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solve for x x^2 -x+6=0 solve, give exact and approx to 3 decimals x^2+7x-5
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2nd equation =o, sorry!
that makes the equation be x^2-x-6 tho not +6
quadratic formula then \[x=(-b \pm \sqrt{b ^{2}-4ac})\div2a\] \[x=(1\pm \sqrt{1-4\times1\times6})\div2\times1\] \[x=1\pm \sqrt{-25}\div2\] you cannot sqare root a negative so there are no answers to the first part
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