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OpenStudy (anonymous):
A basketball team has eight players. What is the probability that at least two of them were born on th same day of the week?
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OpenStudy (amistre64):
hmmm ...... each player has the probability of 1/7
OpenStudy (jamesj):
Actually, just think this through. 8 players, 7 days. Is it possible that they are all born on different days?
OpenStudy (amistre64):
1 -
(C(8,0) (1/7)^0 (6/7)^8
+C(8,1) (1/7)^1 (6/7)^7)
maybe?
OpenStudy (jamesj):
If they were all born on different days, then there would be at least 8 days in a week. But they're aren't. Hence ...
OpenStudy (anonymous):
christ am i an idiot
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OpenStudy (jamesj):
Not usually, but today ;-)
OpenStudy (amistre64):
id say im on par lol
OpenStudy (anonymous):
that is for sure. so thrilled about doing birthday problem that i forgot to read it. but i wonder if we would get one doing it the stupid way?
OpenStudy (jamesj):
Hopefully.
@Ujuge: are you following my argument?
OpenStudy (anonymous):
yep.
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OpenStudy (jamesj):
Great.
OpenStudy (anonymous):
so how did you solve this?
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