Question

verify that is an indentity
Sin(x-y)=(1-cotx tany)/(csc x sec y)

Answer 1

\[\frac{1-\cot(x)\tan(y)}{\csc(x) \sec(y)}=\frac{1-\frac{\cos(x)}{\sin(x)} \frac{\sin(y)}{\cos(y)}}{\frac{1}{\sin(x)} \frac{1}{\cos(y)}} \cdot \frac{\sin(x)\cos(y)}{\sin(x)\cos(y)}\]
\[=\frac{\sin(x)\cos(y)-\cos(x)\sin(y)}{1}\]
you got it from here right?

Answer 2

nope

Answer 3

good thing i wasn't asking you then lol

Answer 4

what do i do with the "1" in the denominator?

Answer 5

a/1=a

Answer 6

lol

Answer 7

good job,ty