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The perimeter of a rectangle is 36 ft. The length is 10 ft longer than the width. find the dimensions. write a system of oinear equations and solve the resulting system. 2x+2y=
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i gave you an answer already down there.
let w = width; L=length; P=2W+2L L=W+10 substitute this for L and 36 for P 36=2W+2(W+10) 36=2W+2W+20 [distribute] 16=4W [collect like terms; subtract 20] 4=W [divide by 4] L=4+10=14
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