Question

Population t years from now:
p(t)=4t+6t^(3/2)+200
a) At what rate will the population be changing 4 years from now?
b) what is the estimated population 4 years from now?

Answer 1

dp(t) /dt = 4 + (6*3t^0.5)/2
dp(t) /dt = 4 + 9t^0.5

a) plug t = 4
4+ 9*2 = 22

b) p(4) = 4*4 + 6*4^(3/2) + 200 = 216 + 6 * 8 = 264