Question

a ball is fired vertically into the air. Its height in feet t seconds later in feet t seconds later is given by the formula: h(t)= -2t^2+80t
a) what is the height of the ball after 3 sec?
b) what is the velocity of the ball after 5 sec?
c) when does the ball reach its man height?
d) what is the max height the ball reaches?

Answer 1

For a and b, just substitute the value of t.

a. h(3) = -2 (3^2) + 80 (3)
h(3)= -2(9) + 240
h(3) = -18 + 240
h(3) = 222

So, the ball is 222 feet from the ground.
You should be able to solve for letter b now :)

For c, you should use the formula -b/2a.
For d, you should use the formula c^2(h)(a)

Answer 2

Given the equation h(t) = -2t^2 +80t + 0 wherein -2= a, 80= b and 0 =c

Answer 3

** For d, its c^2-h(a) My bad :D