Question

find the equation of the line tangent to the graph of h(x)=x^4-5x+2 at the point with x-coordinate 1.

Answer 1

find the derivative; sub x=1 to get the slope; ;sub x=1 into h to get the point

Answer 2

h'(x)=4x^3-5
slope is h'(1)=-1
y-coordinate is h(1)=...=-2, so point is (1,-2)
y+2=-(x-1)
or
y=-x-1

Answer 3

thank you.

Answer 4

:})