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Find exact value if: 0 < x < pi/2. and 0 < y < pi/2 Sin ( x-y) if sin x = 3/5 and sin y= 4/5
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sin(x-y)=sin(x)cos(y)-cos(x)cos(y) sin(x)=3/5 ==> cos(x)=4/5, and sin(y)=4/5 ==> cos(y)=3/5 sin(x-y)=(3/5)(4/5)-(4/5)((3/5) =0
your answer is the same my,but the key is :24/25
that would be the answer for sin(x+y)
tk any way
I check (x-y) not (x+y) don't worry
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tk any way
your answer is the same my,but the key is :24/25
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