Question

Evaluate the following limit using the squeeze thereom

lim 2xcos2x as x->0

Answer 1

\[-2|x|\le2x\cos2x\le2|x|\]

Answer 2

i dont know how to go on

Answer 3

then you need to review what the squeeze theorem says. It is really easy from here.

Answer 4

can u explain?

Answer 5

hwo 2 go on then

Answer 6

\[\text{you have 3 parts here...take the limit as }x\to 0\text{ of the left and right sides}\]

if the limits are the same then the middles term also goes to the same value

Answer 7

what are ...

\[\lim_{x\to 0}-2|x|\] and \[\lim_{x\to 0}\,\,2|x|\]

Answer 8

1st one is -2 adn teh second one is 2

Answer 9

no...try again

Answer 10

well does it exist then

Answer 11

yes

Answer 12

i really dont know

Answer 13

i havent evn learned this thereom yet