x^2-3x=-10 use the quadratic formula to solve.
make it equal to zero then substitute the values straight in
i did that and got a wierd answer,
it looks like it has complex roots, not real ones http://www.wolframalpha.com/input/?i=x^2-3x%3D-10
we cant write it like that..
Molly!!!
x^2 - 3x + 10 = 0 then use the quardratic formula to solve. -b^2 plus minus squareroot of b^2 - 4ac , devide by 2a .
oh...its been stated >< hee
i did that but im still confused by it.
oh u'd normally get a fraction. or decimal. confusied by wat?
just th answer and how you get it
chk your email molly
oh. that is the formula. standard formula, if you cant factorize the usual way. the answer you will get from the formula is x itself. got it? =)
x2 -3x+10=0 x_1,_2=(3+/-sqrt(9-40))/2=(3+/- isqrt(31))/2
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