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Mathematics 19 Online
OpenStudy (anonymous):

find f' of f(x)=(cscx)(cotx)

OpenStudy (turingtest):

f'(x)=(cscx)'(cotx)+(cscx)(cotx)' \[=(-\csc x \cot x)(\cot x)+(\csc x)(-\csc^2 x)=-\csc x \cot^2 x-\csc^3 x\]

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