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solve using substitution: 4x+6y=-9 -3x-10y=-11
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Hey, someoneelse-man!
waz up seafood!!!
do u want the answers?
kk i need help..i hate tese problems, can u show me how to do them
Dont sleep in class.
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i do not sleep in class!! ma dumb teacher doesnt give us notes, jus tells us to look it up in our text books
this is harder than that.. i dunno wat to plug in...
4x+6y=-9 -3x-10y=-11 y = (-9 - 4x)/6 y = (-11 + 3x)/-10 y = y -10(-9-4x) = 6(-11+ 3x) 90 + 40x = -66+18x 40x-18x = -66-90 22x = -156 x = -156/22 = -78/11 Good luck finding y
solve the first equation for x: 4x+6y=-9 x = (-9 -6y)/y Now, substitute this equation in eq2: -3x-10y=-11 -3( (-9 -6y)/y)-10y=-11
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