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3/g+1/+5=7
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\[g=\frac{15}{34} \]
how did u get that???
With no imbedded parentheses in your expression and using the C programming language Precedence rules table, http://www.difranco.net/cop2220/op-prec.htm , the expression was viewed as follows:\[(3/g)+(1/+5)=7 \]\[\frac{3}{g}+\frac{1}{5}=7 \]\[\frac{15+g}{5 g}=7 \]\[15+g=7*5 g \]\[15=34 g \]\[g= \frac{15}{34} \]
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