help here make the curve y=ax^4+bx^3+cx^2+dx+e have a critical point at (0,3) and have an inflection point at (1,2) with inflection tangent 6x+y=8

Question

anonymous · Answer

what the monkey is an "inflection tangent"?

anonymous · Answer

YEAH THATS THE CASE WHAT ON EARTH IS INFECTION TANGENT HA!? hahah its on my book god...

myininaya · Answer

i just figured it meant the slope of y''

anonymous · Answer

o?

myininaya · Answer

i mean the equation of the tangent line of y'' at (1,2)

myininaya · Answer

but i could be wrong since i never heard of one

myininaya · Answer

but we need find values for a,b,c,d above

anonymous · Answer

i have the answer here... a=9 b =-22 c=12 d=3

myininaya · Answer

lol

anonymous · Answer

but i dont know how to do xD

myininaya · Answer

d=3 is what i got but i failed at the other values

anonymous · Answer

o my... oops d= 0 e= 3

anonymous · Answer

a=9 b =-22 c=12 d=0 e =3

myininaya · Answer

oh wait i did make a mistake

myininaya · Answer

let me try this again i want to watch tv
but i will see what i can figure out

anonymous · Answer

because it has critical point at (0.3) then y'=4ax^3+3bx^2+2cx+d substitute leads to 0=d

myininaya · Answer

yep e=3 for sure

myininaya · Answer

i will be back ok

anonymous · Answer

ok

myininaya · Answer

i'm still stuck on the inflection tangent i just don't know what that is 
every way i tried to think of what it means it doesn't work out