Question

plz help me in math in this question

5a+3x 3b+2x 6a-b
------ + -------- - -------
4 3 2

Answer 1

no

Answer 2

\[\frac{3(5a+3x)+4(3b+2x)}{12}-\frac{6a-b}{2}\]
\[\frac{15a+9x+12b+8x}{12}-\frac{6a-b}{2}\]
\[\frac{15a+12b+17x}{12}-\frac{6a-b}{2}\]
\[\frac{15a+12b+17x-6(6a-b)}{12}\]
\[\frac{15a+12b+17x-36a+6b}{12}\]
\[\frac{-21a+18b+17x}{12}\]