5a+3x 3b+2x 6a-b ------ + -------- - ------- =? 4 3 2
\[\frac{3(5a+3x)+4(3b+2x)}{12}-\frac{6a-b}{2}\] \[\frac{15a+9x+12b+8x}{12}-\frac{6a-b}{2}\] \[\frac{15a+12b+17x}{12}-\frac{6a-b}{2}\] \[\frac{15a+12b+17x-6(6a-b)}{12}\] \[\frac{15a+12b+17x-36a+6b}{12}\] \[\frac{-21a+18b+17x}{12}\]
it took a great time to type that all but the answer is right and simplified
wahe guru reply if u have understood it
OH
SO HOW HOW DO U GET +18
12b+6b=18b
\[\frac{3(5a+3x)+4(3b+2x)}{12}-\frac{6a-b}{2}\] \[\frac{15a+9x+12b+8x}{12}-\frac{6a-b}{2}\] \[\frac{15a+12b+17x}{12}-\frac{6a-b}{2}\] \[\frac{15a+12b+17x-6(6a-b)}{12}\] \[\frac{15a+12b+17x-36a+6b}{12}\] \[\frac{15a-36a+17x+12b+6b}{12}\] \[\frac{-21a+18b+17x}{12}\]
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