Question

16x2+8x=0

Answer 1

32+8x=0
8x=32
x=-4

Answer 2

\[16x^2\]
or 16x2 ?

Answer 3

good question

Answer 4

yes cuz the answer is defferent

Answer 5

that is very true

Answer 6

if that was \[16^2 \]then the solve is \[16x^2+8x=0\]=\[16x^2=-8x\]
divide it x
so we have \[16x=-8\]\[x=-0.5\]

Answer 7

ohhh. simple :)

first of all, it is the same as: \[2x^2 + x = 0\]

then follow whatever Abdullah Al-Hagbani said. :D

Answer 8

If its 16x^2 + 8x = 0
8x(2x+1) = 0
x = 0 or x -1/2

Answer 9

x = -1/2

Answer 10

in finally x = -1/2 ..
cuz 16x = -8
then x = -1/2