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Mathematics 10 Online
OpenStudy (anonymous):

solve for x? 2xcosx+sinx=0

OpenStudy (anonymous):

it is two times cos(x)?

OpenStudy (anonymous):

no its 2x

OpenStudy (anonymous):

it is two times cos(x)?

OpenStudy (anonymous):

\[\cos ^{2}+\sin ^{2} = 1\]

OpenStudy (anonymous):

the equation given says 2xcosx+sinx...

OpenStudy (anonymous):

it is two times cos(x)?

OpenStudy (anonymous):

you can go by there

OpenStudy (anonymous):

...?

OpenStudy (anonymous):

you have to relate the equation i give with the one i have, and then you can solve it

OpenStudy (anonymous):

*you have

OpenStudy (anonymous):

im not sure how? :/

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