Question

solve:
(3x-8)(x+1)=(x+1)(x-3)

Answer 1

oops
devide by x+1 both sides so (x is not -1)

3x-8 = x-3
2x = 5
x=2.5

Answer 2

sorry, i am not solving x I'm solving for 0

Answer 3

distribute, combine like term, factor
3x^2-8x+3x-8=x^2-3x+1x-3
subtract x^2 on both sides
2x^2-8x+3x-8=-3x+1x-3
2x^2-5x-8=-2x-3
add 2x
2x^2-3x-5
(x+1)(2x-5)
set each factor equal to 0