Question

help anyone??? Show the work to solve |x+3| +7 less than or equal to 10

Answer 1

\[\left| x+3 \right|+7 \le 10\]
\[\left| x+3 \right| \le 3\]\[-3 \le x+3 \le 3\]\[0 \le x \le 6\]

Answer 2

sorry the last part should be\[-6 \le x \le 0\]

Answer 3

what hapened to the 7?

Answer 4

at the beginning while we still had absolute value signs I subtracted it.

Answer 5

that's why from there on we have < or = to 3

Answer 6

oh okay

Answer 7

|x+3|+7≤10
subtract 7 from both sides:
|x+3|≤3
−3≤x+3≤3
−6≤x≤0
is how I was supposed to write it