Question

Mitch has $4.55 in dimes and quarters on his desk. He has 7 more quarters than dimes. find the number he has of each coin using consecutive integers.

Answer 1

let x = number of dimes; y = number of quarters

10x + 25y = 455 cents
y = 7+x

10x + 25y = 455
(-x + y = 7) 10

10x + 25y = 455
-10x + 10y = 70

35y = 525
y = 15
x = 8

there are 8 dimes and 15 quarters

I'm sorry i can only do it using systems of equations