Completing square (Show Steps):
f(x) = -0.6 x^2+1.2 x+1.4
What is the Domain & Range?
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OpenStudy (anonymous):
what is with you with these problems???
OpenStudy (anonymous):
lets to it the easy way
\[-\frac{b}{2a}=-\frac{1.2}{2\times -.6}=2\] so you will have
\[f(x)=-.6(x-2)^2+\text{something}\] and that "something" is
\[f(2)\]
OpenStudy (saifoo.khan):
f(x) = -(0.6) (x - 1)² + 2
OpenStudy (saifoo.khan):
that's the answer/
OpenStudy (anonymous):
oh cramp that is wrong! it is
\[-\frac{b}{2a}=-\frac{1.2}{2\times -.6}=1\]
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OpenStudy (saifoo.khan):
I didn't liked yesterday one, so made a new one! ;)
OpenStudy (anonymous):
yeah 1 ! my arithmetic is bad
OpenStudy (anonymous):
what is this ? and saifoo you asked a question?! i have only seen you answer them
OpenStudy (anonymous):
so it will be
\[f(x)=-0.6(x-1)^2+\text { whatever } f(1) \text{ is}\]
OpenStudy (saifoo.khan):
haha violinplayer, i suck @ completing square.. so i asked for help! ;)
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OpenStudy (anonymous):
oh
OpenStudy (saifoo.khan):
-0.6 x^2+1.2 x+1.4
\[-0.6(-1)^2 +1.2(-1) + 1.4\]
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