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selections done WITH replacement. In one town, 28% of households have wireless internet service. A. In a group of 6 randomly selected homes from the town what is the probability that none have wireless internet service? B. what is the prob that 6 randomly selected houses all have wireless internet service? C. What is the prob that in a group of 6 randomly selected households, atleast one has internet service?
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28% have wireless so evidently 72% do not. the probability that none have wireless is \[(.72)^6\]
the probability that all 6 do is \[(.28)^6\]
and finally "at least one" means "not none" so take the answer to the first question and subtract it from 1
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