Question

evaluate:
n
Σ {[5-(3k/n)^2]3/n}
k=1

Answer 1

\[\sum_{K=1}^{n} ([5-(3k/n)^2] 3/n\]
In general terms, will be expanded as such:
\[\sum_{k=1}^{n} (15/k- (27n^2)/k^3)\]
which will yield:\[-27/2n-9/(2n^2)+6\]