Find the Length of the arc of the parabola y=4x^2, [0, 1]

Question

anonymous · Answer

Alright so my answer is $$1/16 [ 8\sqrt{65}+archsinh(8) ]$$ however the online program that we use for homework says this is incorrect

anonymous · Answer

i'm wondering whether or not the hyperbolic function is messing things up, because i'm pretty sure that answer is correct

anonymous · Answer

The online program doesn't have an option to put hyperbolic functions in

agreene · Answer

What was the integral that you did to get there? If I'm remembering right $$ArcL=\int\limits_{a}^{b}\sqrt{1+[f'(x)]^2}dx$$and if that is so, I'm not sure how to integrate the resultant.

anonymous · Answer

yeah that's right

agreene · Answer

Well, I dont remember all my methods of integration. And I'm not sure how to integrate that. I assume some trig sub would work, but I cant see it at the moment...

anonymous · Answer

http://www.wolframalpha.com/input/?i=int+0..1++sqrt%7B1%2B64x%5E2%7D

anonymous · Answer

according to wolframa the answer is correct. You should tell your teacher there is a problem with a test  at your next class.